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编写要求:
{kdj三金叉}MA5:=EMA(C,5);MA10:=EMA(C,10);MV5:=EMA(V,5);MV10:=EMA(V,10);K:="KDJ.K"(9,3,3);D:="KDJ.D"(9,3,3);V1:=MA5>REF(MA5,1) AND MA10>REF(MA10,1) AND C>REF(C,1) AND C/O>1.01;VV1:=MV5>REF(MV5,1) AND MV10>=REF(MV10,1) AND V>REF(V,1)*1.2 ;KD1:=K>REF(K,1) AND D>=REF(D,1);VA:COUNT(CROSS(K,D),5)>=1 AND COUNT(CROSS(MA5,MA10),5)>=1 AND COUNT(CROSS(MV5,MV10),5)>=1;{MACD二次金}DIF:=EMA(CLOSE,12)-EMA(CLOSE,26);DEA:=EMA(DIF,9);MACD:=2*(DIF-DEA);A1:=CROSS(DIF,DEA);A2:=REF(A1,1);A3:=COUNT(A2,21);A4:MA(C,5)>MA(C,10) AND MA(C,10)>MA(C,30) AND MA(C,30)>MA(C,60)AND MA(C,60)>MA(C,120) AND MA(C,120)>MA(C,250) ;{去除ST}XG:FINANCE(7)/100000000<15 AND NOT(NAMELIKE('ST')) AND NOT(NAMELIKE('*ST'))AND BARSCOUNT(C)>30 AND DYNAINFO(8)>0 AND C<50;
解答:
MA5:=EMA(C,5);
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