把分时庄高公式中的“庄”出现时做个选股公式
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编写要求:

请老师帮我把分时庄高公式中的“庄”出现时做个选股公式,谢谢!源码:VAR1:=EMA(EMA(CLOSE,13),13);控盘:=(VAR1-REF(VAR1,1))/REF(VAR1,1)*1000;STICKLINE(控盘<0,控盘,0,1,1),COLOR00FF00;STICKLINE(控盘>REF(控盘,1) AND 控盘<0,控盘,0,1,1),COLORFF00FF;无庄控盘:=控盘<0;STICKLINE(控盘>REF(控盘,1) AND 控盘>0,控盘,0,1,1),COLOR0000FF;有庄控盘:=控盘>REF(控盘,1) AND 控盘>0;VAR2:=100*WINNER(CLOSE*0.95);STICKLINE(控盘0,控盘,0,1,1),COLORFFFF00;主力出货:=控盘0;STICKLINE(VAR2>50 AND COST(85)0,控盘,0,1,1),COLOR00FFFF;高度控盘: VAR2>50 AND COST(85)0,ColorFF00FF,LINETHICK2;A10:=CROSS(控盘,0);控盘B:=FILTER(IF(A10,1,0),5);{控盘买卖条件}STJ01:=控盘0.5;STJ02:=控盘>0;BTJ2:=控盘>REF(控盘,1) AND 控盘<-0.2;BTJ22:=控盘>REF(控盘,1) AND 控盘<0 ;{分时价格原码}JJ:=DYNAINFO(11);{波段买卖原码}P:=55;S:=8;M1:=3;能量:(EMA(CLOSE,S)-EMA(C,P))*10,LINETHICK2,COLOR0000FF;空头:EMA(能量,M1),COLOR00FF00;{股价与均线偏离买卖条件}BTJ1:=(CLOSE-JJ)/JJ<-0.005;BTJ11:=(CLOSE-JJ)/JJ<-0.03;BTJ12:=ref(LAST(JJ>=REF(JJ,1)),1)>=4 AND (CLOSE-JJ)/JJ<0.005;STJ1:=(C-JJ)/JJ>0.005;{波段买卖条件}BTJ3:=CROSS(能量,空头) AND 能量<-0.3;BTJ32:=CROSS(能量,空头) AND 能量<-0.1;STJ31:=CROSS(空头,能量);STJ32:=CROSS(空头,能量) AND 能量>1.618;{以下为信号};A:=8;BTJ81:=FILTER(BTJ1 AND BTJ2 AND BTJ3,A);BTJ811:=FILTER(BTJ11 AND BTJ2 AND BTJ3,A);BTJ82:=FILTER(BTJ12 AND BTJ22 AND BTJ32,A);时长:=if(HOUR>=9 AND HOUR<14 ,1,0);{9点至 14点}有庄:BTJ811 AND TIME>15 and 时长,ColorFF8000,STICK,LINETHICK3;DRAWICON(BTJ811 AND TIME>5 and 时长,0,9),ALIGN1;{有庄};DRAWTEXT(BTJ811 AND TIME>5 and 时长,1.5,'庄'),Color00FFFF,ALIGN1;STJ81:=FILTER(STJ1 AND STJ01 AND STJ31,A);STJ82:=FILTER(STJ02 AND STJ32 ,A);STJ83:=STJ81 AND STJ82;DRAWTEXT(STJ83,空头,'卖'),ColorFFFFFF,ALIGN1;{量价新高}T:=BARSCOUNT(CLOSE);分钟数:=IF(TIME0/60-570<=130,TIME0/60-570,TIME0/60-660);AA:=VOL/((HIGH-LOW)*2-ABS(CLOSE-OPEN));主买:=IF(CLOSE>OPEN,AA*(HIGH-LOW),IF(CLOSEOPEN,0-AA*((HIGH-CLOSE)+(OPEN-LOW)),IF(CLOSE0 AND 价新高>REF(价新高,1) AND 量新高>REF(量新高,1) AND 净流入>0,Color00FFFF,STICK,linethick3;

解答:

 P:=55;S:=8;M1:=3;

能量:=(EMA(CLOSE,S)-EMA(C,P))*10;
VAR1:=EMA(EMA(CLOSE,13),13);
空头:=EMA(能量,M1);
控盘:=(VAR1-REF(VAR1,1))/REF(VAR1,1)*1000;
BTJ2:=控盘>REF(控盘,1) AND 控盘<-0.2;
JJ:=DYNAINFO(11);
BTJ11:=(CLOSE-JJ)/JJ<-0.03;
BTJ3:=CROSS(能量,空头) AND  能量<-0.3;
A:=8;
BTJ811:=FILTER(BTJ11 AND BTJ2 AND BTJ3,A);
时长:=IF(HOUR>=9 AND HOUR<14 ,1,0);{9点至 14点}
BTJ811 AND TIME>5 AND 时长;
 

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