星星索改成大智慧
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C<EXPMA(C,12)/1.05 AND
BETWEEN(CCI.CCI,-200,-100) AND
KDJ.J<10 AND
REF(KDJ.J,2)>REF(KDJ.J,1) AND
KDJ.J>REF(KDJ.J,1) AND
EVERY(BETWEEN(ABS(C-O)/O,0.001,0.005),2);
 

 
解答如下：
TYP := (HIGH + LOW + CLOSE)/3;
CCI:=(TYP-MA(TYP,14))/(0.015*AVEDEV(TYP,14));
C<EMA(C,12)/1.05 AND
BETWEEN(CCI,-200,-100) AND
"KDJ.J"<10 AND
REF("KDJ.J",2)>REF("KDJ.J",1) AND
"KDJ.J">REF("KDJ.J",1) AND
ALL(BETWEEN(ABS(C-O)/O,0.001,0.005),2);
 

 


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